- 192.168.100.1 /28
255.255.255.0 (255 mewakili 8bit)(8bit x 3 = 28)
-172.16.100.100 /16
255.255.0.0 (255 mewakili 8bit)(8bit x 2 = 16)
- 10.1.100.1 /8
255.0.0.0 (255 mewakili 8bit)(8bit x 1 = 8)
*Network Address & Broadcase Address
- network address merupakan first address (alamat pertama)
- broadcase address merupakan last address (alamat akhir)
192.168.100.10
255.255.255.0
192.168.100.0 <- network address
192.168.100.255 <- broadcase address
Formula :-
HOST
Class A:2n – 2 ; kenapa perlu tolak 2, sbb dlm host ada net address dan broadcast
Address
Cara nak kira lebihan ID.
Contoh:
192.168.100.10/25
192.168.100.1/31
172.16.100.1/18
10.10.10.10/15
172.30.30.30/23
192.168.10.10/24
Mula2 mesti kena kenal ID dok lam clz mane
Lepas 2 tgk dia pnye CIDR.
Contohnya:
192.168.100.10/25 = class C
255.255.255.0
2n = 21 (lebihan bit network dalam host oktet)
= 2, net address
2n = 27 (lebihan bit host dalam host oktet)
= 128 -2 = 126 usable host (-2, include net & broadcast)
192.168.100.1/31 = class C
255.255.255.0
2n = 27 (lebihan bit network dalam host oktet)
= 128, net address
2n = 21 (lebihan bit host dalam host oktet)
= 2 -2 = 0 usable host (-2, include net & broadcast)
172.16.100.1/18 = class B
255.255.0.0
2n = 22 (lebihan bit network dalam host oktet)
= 4, net address
2n = 214 (lebihan bit host dalam host oktet)
= 16384 -2 = 16382 usable host (-2, include net & broadcast)
10.10.10.10/15 = class A
255.0.0.0
2n = 27 (lebihan bit network dalam host oktet)
= 128, net address
2n = 217 (lebihan bit host dalam host oktet)
= 131072 -2 = 131070 usable host (-2, include net & broadcast)
172.30.30.30/23 = class B
255.255.0.0
2n = 27 (lebihan bit network dalam host oktet)
= 128, net address
2n = 29 (lebihan bit host dalam host oktet)
= 512 -2 = 510 usable host (-2, include net & broadcast)
192.168.10.10/24 = class C
255.255.255.0
2n = 20 (lebihan bit network dalam host oktet)
= 1, net address
2n = 28 (lebihan bit host dalam host oktet)
= 256 -2 = 254 usable host (-2, include net & broadcast)
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